SEED continues to make mistakes.
So is today’s challenge:
#includeint main(int argc, char *argv[]) { printf("%d",4["seed"]); return 0; }
The answer for the above is 0, as the fourth element in the array “seed” does not exist. This is because of the index value, which starts from 0. Had it been 3, then it would print out the character code for d, and that would be the right answer.
However, none of the options had the value 0, they had some other values.
@SEEDInfotech, why make such obvious mistakes on your side? Didn’t you already learn from my last post? There simply is no room for such mistakes!
Isn’t there any moderator smart enough in your company?
@SEEDInfotech #iknowvention
Here’s the link to the previous post: http://judepereira.com/blog/seed-makes-blunder-iknowvention/
how is main() invoked ? What are the parameters when invoking main ()
Francis, it doesn’t matter how main() is invoked, as none of those variables are being used.